Complex conjugate vector space.html

 
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In mathematics, one associates to every complex vector space V\, its complex conjugate vector space \overline V, again a complex vector space. One reason for considering the conjugate vector space is that it allows one to think of antilinear maps as linear maps: an antilinear map from V\, to W\, gives rise to a linear map \overline V\to W, and conversely.

The underlying set of vectors and the addition of \overline V are the same as those of V\,, but the scalar multiplication in \overline V is defined as follows:

to multiply the complex number \alpha\, with the vector v\, in \overline V, take the complex conjugate \bar \alpha of \alpha\, and multiply it with v\, in the original space V\,.

The map \overline{(\,\cdot\,)}: V\to\overline V defined by \overline v= v for all v\, in V\, is then bijective and antilinear. Furthermore, we have \overline{\overline V}= V and \overline{\overline v}=v for all v\, in V\,.

An antilinear map V \to W, for another vector space W\,, is the same thing as a linear map \overline V\to W.

Given a linear map f:V\to W, the conjugate linear map \overline f:\overline V\to \overline W is defined by the formula:

\overline f(\overline v)=\overline{f(v)}.

The conjugate linear map \overline f is linear. Moreover, the rules V\mapsto \overline V and f\mapsto\overline f define a functor from the category of C-vector spaces to itself.

If V\, and W\, are finite-dimensional and the map f\, is described by the matrix A\, with respect to the bases \mathcal B of V\, and \mathcal C of W\,, then the map \overline f is described by the complex conjugate of A\, with respect to the bases \overline{\mathcal B} of \overline V and \overline{\mathcal C} of \overline W.

The vector spaces V\, and \overline V have the same dimension over C and are therefore isomorphic as C-vector spaces. However, there is no natural isomorphism from V\, to \overline V.

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